Solve 0 * 16; (3x - 2) = 0.4x + 7 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$-0\cdot16; (3x-2)=0.4x+7$$

Solve for x, y

$y=0$

Solution Steps

Consider the first equation. Subtract $0.4x$ from both sides.

$$3x-2-0.4x=7$$

Combine $3x$ and $-0.4x$ to get $2.6x$.

$$2.6x-2=7$$

Add $2$ to both sides.

$$2.6x=7+2$$

Add $7$ and $2$ to get $9$.

$$2.6x=9$$

Divide both sides by $2.6$.

$$x=\frac{9}{2.6}$$

Expand $\frac{9}{2.6}$ by multiplying both numerator and the denominator by $10$.

$$x=\frac{90}{26}$$

Reduce the fraction $\frac{90}{26}$ to lowest terms by extracting and canceling out $2$.

$$x=\frac{45}{13}$$

Consider the second equation. Multiply $0$ and $16$ to get $0$.

$$y=0$$

The system is now solved.

$$x=\frac{45}{13}$$ $$y=0$$