How to solve -1/3+3/5+-5/9

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -1/3+3/5+-5/9 | Equatix

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Question

$$-1/3+3/5+-5/9$$

Evaluate

$-\frac{13}{45}\approx -0.288888889$

Solution Steps

Fraction $\frac{-1}{3}$ can be rewritten as $-\frac{1}{3}$ by extracting the negative sign.

$$-\frac{1}{3}+\frac{3}{5}+\frac{-5}{9}$$

Least common multiple of $3$ and $5$ is $15$. Convert $-\frac{1}{3}$ and $\frac{3}{5}$ to fractions with denominator $15$.

$$-\frac{5}{15}+\frac{9}{15}+\frac{-5}{9}$$

Since $-\frac{5}{15}$ and $\frac{9}{15}$ have the same denominator, add them by adding their numerators.

$$\frac{-5+9}{15}+\frac{-5}{9}$$

Add $-5$ and $9$ to get $4$.

$$\frac{4}{15}+\frac{-5}{9}$$

Fraction $\frac{-5}{9}$ can be rewritten as $-\frac{5}{9}$ by extracting the negative sign.

$$\frac{4}{15}-\frac{5}{9}$$

Least common multiple of $15$ and $9$ is $45$. Convert $\frac{4}{15}$ and $\frac{5}{9}$ to fractions with denominator $45$.

$$\frac{12}{45}-\frac{25}{45}$$

Since $\frac{12}{45}$ and $\frac{25}{45}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{12-25}{45}$$

Subtract $25$ from $12$ to get $-13$.

$$-\frac{13}{45}$$

Show Solution

Factor

$-\frac{13}{45} = -0.28888888888888886$