How to solve -1/4(12x)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -1/4(12x) | Equatix

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Question

$$-1/4(12x)$$

Evaluate

$-3x$

Solution Steps

Fraction $\frac{-1}{4}$ can be rewritten as $-\frac{1}{4}$ by extracting the negative sign.

$$-\frac{1}{4}\times 12x$$

Express $-\frac{1}{4}\times 12$ as a single fraction.

$$\frac{-12}{4}x$$

Divide $-12$ by $4$ to get $-3$.

$$-3x$$

Show Solution

Differentiate w.r.t. x

$-3$

Steps Using Definition of a Derivative

Fraction $\frac{-1}{4}$ can be rewritten as $-\frac{1}{4}$ by extracting the negative sign.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-\frac{1}{4}\times 12x)$$

Express $-\frac{1}{4}\times 12$ as a single fraction.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{-12}{4}x)$$

Divide $-12$ by $4$ to get $-3$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-3x)$$

The derivative of $ax^{n}$ is $nax^{n-1}$.

$$-3x^{1-1}$$

Subtract $1$ from $1$.

$$-3x^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$-3$$