Solve (a) 1 5/8, 1 11/12, - 1 11/16, 17/9, - 1 5/6 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$- 1 \frac { 5 } { 8 } , 1 \frac { 11 } { 12 } , - 1 \frac { 11 } { 16 } , \frac { 17 } { 9 } , - 1 \frac { 5 } { 6 }$$

Sort

$-\frac{11}{6},-\frac{27}{16},-\frac{13}{8},\frac{17}{9},\frac{23}{12}$

Solution Steps

Multiply $1$ and $8$ to get $8$.

$$sort(-\frac{8+5}{8},\frac{1\times 12+11}{12},-\frac{1\times 16+11}{16},\frac{17}{9},-\frac{1\times 6+5}{6})$$

Add $8$ and $5$ to get $13$.

$$sort(-\frac{13}{8},\frac{1\times 12+11}{12},-\frac{1\times 16+11}{16},\frac{17}{9},-\frac{1\times 6+5}{6})$$

Multiply $1$ and $12$ to get $12$.

$$sort(-\frac{13}{8},\frac{12+11}{12},-\frac{1\times 16+11}{16},\frac{17}{9},-\frac{1\times 6+5}{6})$$

Add $12$ and $11$ to get $23$.

$$sort(-\frac{13}{8},\frac{23}{12},-\frac{1\times 16+11}{16},\frac{17}{9},-\frac{1\times 6+5}{6})$$

Multiply $1$ and $16$ to get $16$.

$$sort(-\frac{13}{8},\frac{23}{12},-\frac{16+11}{16},\frac{17}{9},-\frac{1\times 6+5}{6})$$

Add $16$ and $11$ to get $27$.

$$sort(-\frac{13}{8},\frac{23}{12},-\frac{27}{16},\frac{17}{9},-\frac{1\times 6+5}{6})$$

Multiply $1$ and $6$ to get $6$.

$$sort(-\frac{13}{8},\frac{23}{12},-\frac{27}{16},\frac{17}{9},-\frac{6+5}{6})$$

Add $6$ and $5$ to get $11$.

$$sort(-\frac{13}{8},\frac{23}{12},-\frac{27}{16},\frac{17}{9},-\frac{11}{6})$$

Least common denominator of the numbers in the list $-\frac{13}{8},\frac{23}{12},-\frac{27}{16},\frac{17}{9},-\frac{11}{6}$ is $144$. Convert numbers in the list to fractions with denominator $144$.

$$-\frac{234}{144},\frac{276}{144},-\frac{243}{144},\frac{272}{144},-\frac{264}{144}$$

To sort the list, start from a single element $-\frac{234}{144}$.

$$-\frac{234}{144}$$

Insert $\frac{276}{144}$ to the appropriate location in the new list.

$$-\frac{234}{144},\frac{276}{144}$$

Insert $-\frac{243}{144}$ to the appropriate location in the new list.

$$-\frac{243}{144},-\frac{234}{144},\frac{276}{144}$$

Insert $\frac{272}{144}$ to the appropriate location in the new list.

$$-\frac{243}{144},-\frac{234}{144},\frac{272}{144},\frac{276}{144}$$

Insert $-\frac{264}{144}$ to the appropriate location in the new list.

$$-\frac{264}{144},-\frac{243}{144},-\frac{234}{144},\frac{272}{144},\frac{276}{144}$$

Replace the obtained fractions with the initial values.

$$-\frac{11}{6},-\frac{27}{16},-\frac{13}{8},\frac{17}{9},\frac{23}{12}$$

Evaluate

$-\frac{13}{8},\frac{23}{12},-\frac{27}{16},\frac{17}{9},-\frac{11}{6}$