Solve - 1 - (6x + 3) = - 2(8x - 3) + 1 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$-1-(6x+3)=-2(8x-3)+1$$

Solve for x

$x = \frac{11}{10} = 1\frac{1}{10} = 1.1$

Steps for Solving Linear Equation

To find the opposite of $6x+3$, find the opposite of each term.

$$-1-6x-3=-2\left(8x-3\right)+1$$

Subtract $3$ from $-1$ to get $-4$.

$$-4-6x=-2\left(8x-3\right)+1$$

Use the distributive property to multiply $-2$ by $8x-3$.

$$-4-6x=-16x+6+1$$

Add $6$ and $1$ to get $7$.

$$-4-6x=-16x+7$$

Add $16x$ to both sides.

$$-4-6x+16x=7$$

Combine $-6x$ and $16x$ to get $10x$.

$$-4+10x=7$$

Add $4$ to both sides.

$$10x=7+4$$

Add $7$ and $4$ to get $11$.

$$10x=11$$

Divide both sides by $10$.

$$x=\frac{11}{10}$$