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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$-|1+||-||+||-||+||-1|$$

Evaluate

$-2$

Solution Steps

The absolute value of a real number $a$ is $a$ when $a\geq 0$, or $-a$ when $a<0$. The absolute value of $-1$ is $1$.

$$-|1+||-||||-|||1||||||||||$$

The absolute value of a real number $a$ is $a$ when $a\geq 0$, or $-a$ when $a<0$. The absolute value of $1$ is $1$.

$$-|1+||-||||-||1|||||||||$$

The absolute value of a real number $a$ is $a$ when $a\geq 0$, or $-a$ when $a<0$. The absolute value of $1$ is $1$.

$$-|1+||-||||-|1||||||||$$

The absolute value of a real number $a$ is $a$ when $a\geq 0$, or $-a$ when $a<0$. The absolute value of $1$ is $1$.

$$-|1+||-||||-1|||||||$$

The absolute value of a real number $a$ is $a$ when $a\geq 0$, or $-a$ when $a<0$. The absolute value of $-1$ is $1$.

$$-|1+||-|||1||||||$$

The absolute value of a real number $a$ is $a$ when $a\geq 0$, or $-a$ when $a<0$. The absolute value of $1$ is $1$.

$$-|1+||-||1|||||$$

The absolute value of a real number $a$ is $a$ when $a\geq 0$, or $-a$ when $a<0$. The absolute value of $1$ is $1$.

$$-|1+||-|1||||$$

The absolute value of a real number $a$ is $a$ when $a\geq 0$, or $-a$ when $a<0$. The absolute value of $1$ is $1$.

$$-|1+||-1|||$$

The absolute value of a real number $a$ is $a$ when $a\geq 0$, or $-a$ when $a<0$. The absolute value of $-1$ is $1$.

$$-|1+|1||$$

The absolute value of a real number $a$ is $a$ when $a\geq 0$, or $-a$ when $a<0$. The absolute value of $1$ is $1$.

$$-|1+1|$$

Add $1$ and $1$ to get $2$.

$$-|2|$$

The absolute value of a real number $a$ is $a$ when $a\geq 0$, or $-a$ when $a<0$. The absolute value of $2$ is $2$.

$$-2$$

Factor

$-2$