Question

$$-10 { x }^{ 2 } +20x=0$$

Answer

x=0,2

Solution


Factor out the common term \(10x\).
\[-10x(x-2)=0\]
Divide both sides by \(-10\).
\[x(x-2)=0\]
Solve for \(x\).
\[x=0,2\]