Solve -10(x)^(2)+20x,x=1 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$-10 { x }^{ 2 } +20x,x=1$$

Solve for x, y

$y=10$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$y=-10\times 1^{2}+20\times 1$$

Calculate $1$ to the power of $2$ and get $1$.

$$y=-10+20\times 1$$

Multiply $20$ and $1$ to get $20$.

$$y=-10+20$$

Add $-10$ and $20$ to get $10$.

$$y=10$$

The system is now solved.

$$x=1$$ $$y=10$$