Solve -10(x)^(2)+20x,x=10 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$-10 { x }^{ 2 } +20x,x=10$$

Solve for x, y

$y=-800$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$y=-10\times 10^{2}+20\times 10$$

Calculate $10$ to the power of $2$ and get $100$.

$$y=-10\times 100+20\times 10$$

Multiply $-10$ and $100$ to get $-1000$.

$$y=-1000+20\times 10$$

Multiply $20$ and $10$ to get $200$.

$$y=-1000+200$$

Add $-1000$ and $200$ to get $-800$.

$$y=-800$$

The system is now solved.

$$x=10$$ $$y=-800$$