Solve -10(x)^(2)+20x,x=-2 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$-10 { x }^{ 2 } +20x,x=-2$$

Solve for x, y

$y=-80$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$y=-10\left(-2\right)^{2}+20\left(-2\right)$$

Calculate $-2$ to the power of $2$ and get $4$.

$$y=-10\times 4+20\left(-2\right)$$

Multiply $-10$ and $4$ to get $-40$.

$$y=-40+20\left(-2\right)$$

Multiply $20$ and $-2$ to get $-40$.

$$y=-40-40$$

Subtract $40$ from $-40$ to get $-80$.

$$y=-80$$

The system is now solved.

$$x=-2$$ $$y=-80$$