Solve -10-{-2+[+1-(-3-5)+3]} | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$-10- \{ -2+[+1-(-3-5)+3] \}$$

Evaluate

$-20$

Solution Steps

Subtract $5$ from $-3$ to get $-8$.

$$-10-\left(-2+1-\left(-8\right)+3\right)$$

The opposite of $-8$ is $8$.

$$-10-\left(-2+1+8+3\right)$$

Add $1$ and $8$ to get $9$.

$$-10-\left(-2+9+3\right)$$

Add $-2$ and $9$ to get $7$.

$$-10-\left(7+3\right)$$

Add $7$ and $3$ to get $10$.

$$-10-10$$

Subtract $10$ from $-10$ to get $-20$.

$$-20$$

Factor

$-20$