Solve -11+(+8)-13-(+10)+8= | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$-11+(+8)-13-(+10)+8=$$

Evaluate

$-18$

Solution Steps

Add $-11$ and $8$ to get $-3$.

$$-3-13-10+8$$

Subtract $13$ from $-3$ to get $-16$.

$$-16-10+8$$

Subtract $10$ from $-16$ to get $-26$.

$$-26+8$$

Add $-26$ and $8$ to get $-18$.

$$-18$$

Factor

$-18$