$$[-12 \div (2-5)-3.(8 \div 2)] \div [-8 \div (5-7)-16 \div (2-6)]$$
$-1$
$$\frac{\frac{-12}{-3}-3\times \frac{8}{2}}{\frac{-8}{5-7}-\frac{16}{2-6}}$$
$$\frac{4-3\times \frac{8}{2}}{\frac{-8}{5-7}-\frac{16}{2-6}}$$
$$\frac{4-3\times 4}{\frac{-8}{5-7}-\frac{16}{2-6}}$$
$$\frac{4-12}{\frac{-8}{5-7}-\frac{16}{2-6}}$$
$$\frac{-8}{\frac{-8}{5-7}-\frac{16}{2-6}}$$
$$\frac{-8}{\frac{-8}{-2}-\frac{16}{2-6}}$$
$$\frac{-8}{4-\frac{16}{2-6}}$$
$$\frac{-8}{4-\frac{16}{-4}}$$
$$\frac{-8}{4-\left(-4\right)}$$
$$\frac{-8}{4+4}$$
$$\frac{-8}{8}$$
$$-1$$
Show Solution
Hide Solution
