How to solve -12+(-9/11+7/12)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -12+(-9/11+7/12) | Equatix

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Question

$$-12+(-9/11+7/12)$$

Evaluate

$-\frac{1615}{132}\approx -12.234848485$

Solution Steps

Fraction $\frac{-9}{11}$ can be rewritten as $-\frac{9}{11}$ by extracting the negative sign.

$$-12-\frac{9}{11}+\frac{7}{12}$$

Convert $-12$ to fraction $-\frac{132}{11}$.

$$-\frac{132}{11}-\frac{9}{11}+\frac{7}{12}$$

Since $-\frac{132}{11}$ and $\frac{9}{11}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{-132-9}{11}+\frac{7}{12}$$

Subtract $9$ from $-132$ to get $-141$.

$$-\frac{141}{11}+\frac{7}{12}$$

Least common multiple of $11$ and $12$ is $132$. Convert $-\frac{141}{11}$ and $\frac{7}{12}$ to fractions with denominator $132$.

$$-\frac{1692}{132}+\frac{77}{132}$$

Since $-\frac{1692}{132}$ and $\frac{77}{132}$ have the same denominator, add them by adding their numerators.

$$\frac{-1692+77}{132}$$

Add $-1692$ and $77$ to get $-1615$.

$$-\frac{1615}{132}$$

Show Solution

Factor

$-\frac{1615}{132} = -12\frac{31}{132} = -12.234848484848484$