$$[-12 \times (2-5)-3 \times (8/2)]/[-8/(5-7)-16/(2-4)]$$
$2$
$$\frac{-12\left(-3\right)-3\times \frac{8}{2}}{\frac{-8}{5-7}-\frac{16}{2-4}}$$
$$\frac{36-3\times \frac{8}{2}}{\frac{-8}{5-7}-\frac{16}{2-4}}$$
$$\frac{36-3\times 4}{\frac{-8}{5-7}-\frac{16}{2-4}}$$
$$\frac{36-12}{\frac{-8}{5-7}-\frac{16}{2-4}}$$
$$\frac{24}{\frac{-8}{5-7}-\frac{16}{2-4}}$$
$$\frac{24}{\frac{-8}{-2}-\frac{16}{2-4}}$$
$$\frac{24}{4-\frac{16}{2-4}}$$
$$\frac{24}{4-\frac{16}{-2}}$$
$$\frac{24}{4-\left(-8\right)}$$
$$\frac{24}{4+8}$$
$$\frac{24}{12}$$
$$2$$
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