How to solve -14+27-9+8-11+29

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -14+27-9+8-11+29 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$-14+27-9+8-11+29$$

Evaluate

$30$

Solution Steps

Add $-14$ and $27$ to get $13$.

$$13-9+8-11+29$$

Subtract $9$ from $13$ to get $4$.

$$4+8-11+29$$

Add $4$ and $8$ to get $12$.

$$12-11+29$$

Subtract $11$ from $12$ to get $1$.

$$1+29$$

Add $1$ and $29$ to get $30$.

$$30$$

Show Solution

Factor

$2\times 3\times 5$

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