How to solve -15-(4+1/3)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -15-(4+1/3) | Equatix

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$$-15-(4+1/3)$$

$-\frac{58}{3}\approx -19.333333333$

Convert $4$ to fraction $\frac{12}{3}$.

$$-15-\left(\frac{12}{3}+\frac{1}{3}\right)$$

Since $\frac{12}{3}$ and $\frac{1}{3}$ have the same denominator, add them by adding their numerators.

$$-15-\frac{12+1}{3}$$

Add $12$ and $1$ to get $13$.

$$-15-\frac{13}{3}$$

Convert $-15$ to fraction $-\frac{45}{3}$.

$$-\frac{45}{3}-\frac{13}{3}$$

Since $-\frac{45}{3}$ and $\frac{13}{3}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{-45-13}{3}$$

Subtract $13$ from $-45$ to get $-58$.

$$-\frac{58}{3}$$

$-\frac{58}{3} = -19\frac{1}{3} = -19.333333333333332$