How to solve -16=32-2/5

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -16=32-2/5 | Equatix

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3(r+2s)=2t-4

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Question

$$-16=32-2/5$$

Verify

$\text{false}$

Solution Steps

Convert $32$ to fraction $\frac{160}{5}$.

$$-16=\frac{160}{5}-\frac{2}{5}$$

Since $\frac{160}{5}$ and $\frac{2}{5}$ have the same denominator, subtract them by subtracting their numerators.

$$-16=\frac{160-2}{5}$$

Subtract $2$ from $160$ to get $158$.

$$-16=\frac{158}{5}$$

Convert $-16$ to fraction $-\frac{80}{5}$.

$$-\frac{80}{5}=\frac{158}{5}$$

Compare $-\frac{80}{5}$ and $\frac{158}{5}$.

$$\text{false}$$

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