How to solve -16=32-2/5x

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -16=32-2/5x | Equatix

Integers & Absolute Values

Factors & Multiples

Prime Factorization

Basic Equations & Inequalities

Coordinate Plane & Graphing

Linear Equations & Inequalities

Quadratic Equations

Polynomials & Factoring

Functions & Graphs

Systems of Equations

Trigonometric Functions

Trigonometric Identities & Equations

Right Triangle Trigonometry

Unit Circle

Graphing Trigonometric Functions

Limits & Continuity

Derivatives & Applications

Integrals & Applications

Series & Sequences

Multivariable Calculus

Functions & Graphs

Polynomial & Rational Functions

Exponential & Logarithmic Functions

Conic Sections

Sequences & Series

Descriptive Statistics

Eigenvalues & Eigenvectors

Linear Transformations

Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$-16=32-2/5x$$

Solve for x

$x=120$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$32-\frac{2}{5}x=-16$$

Subtract $32$ from both sides.

$$-\frac{2}{5}x=-16-32$$

Subtract $32$ from $-16$ to get $-48$.

$$-\frac{2}{5}x=-48$$

Multiply both sides by $-\frac{5}{2}$, the reciprocal of $-\frac{2}{5}$.

$$x=-48\left(-\frac{5}{2}\right)$$

Express $-48\left(-\frac{5}{2}\right)$ as a single fraction.

$$x=\frac{-48\left(-5\right)}{2}$$

Multiply $-48$ and $-5$ to get $240$.

$$x=\frac{240}{2}$$

Divide $240$ by $2$ to get $120$.

$$x=120$$

Show Solution

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Example

Question

Solve for x

Steps for Solving Linear Equation