Solve -19+(-9\times12+8)\div(-8+33)= | Equatix - Math Solver

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$-19+(-9 \times 12+8) \div (-8+33)=$$

Evaluate

$-23$

Solution Steps

Multiply $-9$ and $12$ to get $-108$.

$$-19+\frac{-108+8}{-8+33}$$

Add $-108$ and $8$ to get $-100$.

$$-19+\frac{-100}{-8+33}$$

Add $-8$ and $33$ to get $25$.

$$-19+\frac{-100}{25}$$

Divide $-100$ by $25$ to get $-4$.

$$-19-4$$

Subtract $4$ from $-19$ to get $-23$.

$$-23$$

Factor

$-23$