Question

$$-2 { x }^{ 2 } +8x=0$$

Answer

x=0,4

Solution


Factor out the common term \(2x\).
\[-2x(x-4)=0\]
Divide both sides by \(-2\).
\[x(x-4)=0\]
Solve for \(x\).
\[x=0,4\]