Solve -2(3x-5)+4(6-2x)=10x+6 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$-2(3x-5)+4(6-2x)=10x+6$$

Solve for x

$x = \frac{7}{6} = 1\frac{1}{6} \approx 1.166666667$

Steps for Solving Linear Equation

Use the distributive property to multiply $-2$ by $3x-5$.

$$-6x+10+4\left(6-2x\right)=10x+6$$

Use the distributive property to multiply $4$ by $6-2x$.

$$-6x+10+24-8x=10x+6$$

Add $10$ and $24$ to get $34$.

$$-6x+34-8x=10x+6$$

Combine $-6x$ and $-8x$ to get $-14x$.

$$-14x+34=10x+6$$

Subtract $10x$ from both sides.

$$-14x+34-10x=6$$

Combine $-14x$ and $-10x$ to get $-24x$.

$$-24x+34=6$$

Subtract $34$ from both sides.

$$-24x=6-34$$

Subtract $34$ from $6$ to get $-28$.

$$-24x=-28$$

Divide both sides by $-24$.

$$x=\frac{-28}{-24}$$

Reduce the fraction $\frac{-28}{-24}$ to lowest terms by extracting and canceling out $-4$.

$$x=\frac{7}{6}$$