How to solve -22[(-25)+(-2)-8]

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -22[(-25)+(-2)-8] | Equatix

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3(r+2s)=2t-4

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3(r+2s)=2t-4

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Question

$$-22[(-25)+(-2)-8]$$

Evaluate

$770$

Solution Steps

Subtract $2$ from $-25$ to get $-27$.

$$-22\left(-27-8\right)$$

Subtract $8$ from $-27$ to get $-35$.

$$-22\left(-35\right)$$

Multiply $-22$ and $-35$ to get $770$.

$$770$$

Show Solution

Factor

$2\times 5\times 7\times 11$

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