Solve - 2x ^ 2 + x - 4 = - x ^ 2 + 5x + (x - x ^ 2) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$-2x^{2}+x-4=-x^{2}+5x+(x-x^{2})$$

Solve for x

$x=-\frac{4}{5}=-0.8$

Steps for Solving Linear Equation

Combine $5x$ and $x$ to get $6x$.

$$-2x^{2}+x-4=-x^{2}+6x-x^{2}$$

Add $x^{2}$ to both sides.

$$-2x^{2}+x-4+x^{2}=6x-x^{2}$$

Combine $-2x^{2}$ and $x^{2}$ to get $-x^{2}$.

$$-x^{2}+x-4=6x-x^{2}$$

Subtract $6x$ from both sides.

$$-x^{2}+x-4-6x=-x^{2}$$

Combine $x$ and $-6x$ to get $-5x$.

$$-x^{2}-5x-4=-x^{2}$$

Add $x^{2}$ to both sides.

$$-x^{2}-5x-4+x^{2}=0$$

Combine $-x^{2}$ and $x^{2}$ to get $0$.

$$-5x-4=0$$

Add $4$ to both sides. Anything plus zero gives itself.

$$-5x=4$$

Divide both sides by $-5$.

$$x=\frac{4}{-5}$$

Fraction $\frac{4}{-5}$ can be rewritten as $-\frac{4}{5}$ by extracting the negative sign.

$$x=-\frac{4}{5}$$