Solve - 2x ^ 2 + x + 7 = - x ^ 2 + 5x + (- 2 - x ^ 2) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$-2x^{2}+x+7=-x^{2}+5x+(-2-x^{2})$$

Solve for x

$x = \frac{9}{4} = 2\frac{1}{4} = 2.25$

Steps for Solving Linear Equation

Add $x^{2}$ to both sides.

$$-2x^{2}+x+7+x^{2}=5x-2-x^{2}$$

Combine $-2x^{2}$ and $x^{2}$ to get $-x^{2}$.

$$-x^{2}+x+7=5x-2-x^{2}$$

Subtract $5x$ from both sides.

$$-x^{2}+x+7-5x=-2-x^{2}$$

Combine $x$ and $-5x$ to get $-4x$.

$$-x^{2}-4x+7=-2-x^{2}$$

Add $x^{2}$ to both sides.

$$-x^{2}-4x+7+x^{2}=-2$$

Combine $-x^{2}$ and $x^{2}$ to get $0$.

$$-4x+7=-2$$

Subtract $7$ from both sides.

$$-4x=-2-7$$

Subtract $7$ from $-2$ to get $-9$.

$$-4x=-9$$

Divide both sides by $-4$.

$$x=\frac{-9}{-4}$$

Fraction $\frac{-9}{-4}$ can be simplified to $\frac{9}{4}$ by removing the negative sign from both the numerator and the denominator.

$$x=\frac{9}{4}$$