$$-3-1y-2-3=$$
$-y-8$
$$-5-y-3$$
$$-8-y$$
Show Solution
Hide Solution
$-1$
$$\frac{\mathrm{d}}{\mathrm{d}y}(-5-y-3)$$
$$\frac{\mathrm{d}}{\mathrm{d}y}(-8-y)$$
$$-y^{1-1}$$
$$-y^{0}$$
$$-1$$