How to solve -3-3x > 7x-9

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -3-3x > 7x-9 | Equatix

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Question

$$-3-3x > 7x-9$$

Solve for x

$x<\frac{3}{5}$

Solution Steps

Subtract $7x$ from both sides.

$$-3-3x-7x>-9$$

Combine $-3x$ and $-7x$ to get $-10x$.

$$-3-10x>-9$$

Add $3$ to both sides.

$$-10x>-9+3$$

Add $-9$ and $3$ to get $-6$.

$$-10x>-6$$

Divide both sides by $-10$. Since $-10$ is negative, the inequality direction is changed.

$$x<\frac{-6}{-10}$$

Reduce the fraction $\frac{-6}{-10}$ to lowest terms by extracting and canceling out $-2$.

$$x<\frac{3}{5}$$

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