Solve -[3-(3-3I)+2I]\divI12 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$-[3-(3-3I)+2I] \div I12$$

Evaluate

$-\frac{5I}{I_{12}}$

Solution Steps

To find the opposite of $3-\left(3-3I\right)+2I$, find the opposite of each term.

$$\frac{-3-\left(-\left(3-3I\right)\right)-2I}{I_{12}}$$

The opposite of $-\left(3-3I\right)$ is $3-3I$.

$$\frac{-3+3-3I-2I}{I_{12}}$$

Add $-3$ and $3$ to get $0$.

$$\frac{-3I-2I}{I_{12}}$$

Combine $-3I$ and $-2I$ to get $-5I$.

$$\frac{-5I}{I_{12}}$$

Show Solution

Expand

$-\frac{5I}{I_{12}}$

Solution Steps

To find the opposite of $3-\left(3-3I\right)+2I$, find the opposite of each term.

$$\frac{-3-\left(-\left(3-3I\right)\right)-2I}{I_{12}}$$

The opposite of $-\left(3-3I\right)$ is $3-3I$.

$$\frac{-3+3-3I-2I}{I_{12}}$$

Add $-3$ and $3$ to get $0$.

$$\frac{-3I-2I}{I_{12}}$$

Combine $-3I$ and $-2I$ to get $-5I$.

$$\frac{-5I}{I_{12}}$$

Show Solution

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Solution Steps