How to solve -3-x > 4x+7

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -3-x > 4x+7 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$-3-x > 4x+7$$

Solve for x

$x<-2$

Solution Steps

Subtract $4x$ from both sides.

$$-3-x-4x>7$$

Combine $-x$ and $-4x$ to get $-5x$.

$$-3-5x>7$$

Add $3$ to both sides.

$$-5x>7+3$$

Add $7$ and $3$ to get $10$.

$$-5x>10$$

Divide both sides by $-5$. Since $-5$ is negative, the inequality direction is changed.

$$x<\frac{10}{-5}$$

Divide $10$ by $-5$ to get $-2$.

$$x<-2$$

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Question

Solve for x

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