How to solve -3(2x-3)+1=16

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -3(2x-3)+1=16 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$-3(2x-3)+1=16$$

Solve for x

$x=-1$

Steps for Solving Linear Equation

Use the distributive property to multiply $-3$ by $2x-3$.

$$-6x+9+1=16$$

Add $9$ and $1$ to get $10$.

$$-6x+10=16$$

Subtract $10$ from both sides.

$$-6x=16-10$$

Subtract $10$ from $16$ to get $6$.

$$-6x=6$$

Divide both sides by $-6$.

$$x=\frac{6}{-6}$$

Divide $6$ by $-6$ to get $-1$.

$$x=-1$$

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Question

Solve for x

Steps for Solving Linear Equation