Solve - 3(x + 3) - 5(2x - 2) + 2 = 0 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$-3(x+3)-5(2x-2)+2=0$$

Solve for x

$x=\frac{3}{13}\approx 0.230769231$

Steps for Solving Linear Equation

Use the distributive property to multiply $-3$ by $x+3$.

$$-3x-9-5\left(2x-2\right)+2=0$$

Use the distributive property to multiply $-5$ by $2x-2$.

$$-3x-9-10x+10+2=0$$

Combine $-3x$ and $-10x$ to get $-13x$.

$$-13x-9+10+2=0$$

Add $-9$ and $10$ to get $1$.

$$-13x+1+2=0$$

Add $1$ and $2$ to get $3$.

$$-13x+3=0$$

Subtract $3$ from both sides. Anything subtracted from zero gives its negation.

$$-13x=-3$$

Divide both sides by $-13$.

$$x=\frac{-3}{-13}$$

Fraction $\frac{-3}{-13}$ can be simplified to $\frac{3}{13}$ by removing the negative sign from both the numerator and the denominator.

$$x=\frac{3}{13}$$