Question

$$-3(x+3)-5(3x-2)\mapsto4=0$$

Answer

m=-(3*(x+3))/(20*a*p*s*t*o*(3*x-2))

Solution


Simplify  \(5(3x-2)mapsto\times 4\)  to  \(20mapsto(3x-2)\).
\[-3(x+3)-20mapsto(3x-2)=0\]
Add \(3(x+3)\) to both sides.
\[-20mapsto(3x-2)=3(x+3)\]
Divide both sides by \(-20\).
\[mapsto(3x-2)=-\frac{3(x+3)}{20}\]
Divide both sides by \(a\).
\[mpsto(3x-2)=-\frac{\frac{3(x+3)}{20}}{a}\]
Simplify  \(\frac{\frac{3(x+3)}{20}}{a}\)  to  \(\frac{3(x+3)}{20a}\).
\[mpsto(3x-2)=-\frac{3(x+3)}{20a}\]
Divide both sides by \(p\).
\[msto(3x-2)=-\frac{\frac{3(x+3)}{20a}}{p}\]
Simplify  \(\frac{\frac{3(x+3)}{20a}}{p}\)  to  \(\frac{3(x+3)}{20ap}\).
\[msto(3x-2)=-\frac{3(x+3)}{20ap}\]
Divide both sides by \(s\).
\[mto(3x-2)=-\frac{\frac{3(x+3)}{20ap}}{s}\]
Simplify  \(\frac{\frac{3(x+3)}{20ap}}{s}\)  to  \(\frac{3(x+3)}{20aps}\).
\[mto(3x-2)=-\frac{3(x+3)}{20aps}\]
Divide both sides by \(t\).
\[mo(3x-2)=-\frac{\frac{3(x+3)}{20aps}}{t}\]
Simplify  \(\frac{\frac{3(x+3)}{20aps}}{t}\)  to  \(\frac{3(x+3)}{20apst}\).
\[mo(3x-2)=-\frac{3(x+3)}{20apst}\]
Divide both sides by \(o\).
\[m(3x-2)=-\frac{\frac{3(x+3)}{20apst}}{o}\]
Simplify  \(\frac{\frac{3(x+3)}{20apst}}{o}\)  to  \(\frac{3(x+3)}{20apsto}\).
\[m(3x-2)=-\frac{3(x+3)}{20apsto}\]
Divide both sides by \(3x-2\).
\[m=-\frac{\frac{3(x+3)}{20apsto}}{3x-2}\]
Simplify  \(\frac{\frac{3(x+3)}{20apsto}}{3x-2}\)  to  \(\frac{3(x+3)}{20apsto(3x-2)}\).
\[m=-\frac{3(x+3)}{20apsto(3x-2)}\]