Question

$$-3+27 { x }^{ 2 } =0$$

Answer

x=1/3,-1/3

Solution


Regroup terms.
\[27{x}^{2}-3=0\]
Add \(3\) to both sides.
\[27{x}^{2}=3\]
Divide both sides by \(27\).
\[{x}^{2}=\frac{3}{27}\]
Simplify  \(\frac{3}{27}\)  to  \(\frac{1}{9}\).
\[{x}^{2}=\frac{1}{9}\]
Take the square root of both sides.
\[x=\pm \sqrt{\frac{1}{9}}\]
Simplify  \(\sqrt{\frac{1}{9}}\)  to  \(\frac{\sqrt{1}}{\sqrt{9}}\).
\[x=\pm \frac{\sqrt{1}}{\sqrt{9}}\]
Simplify  \(\sqrt{1}\)  to  \(1\).
\[x=\pm \frac{1}{\sqrt{9}}\]
Since \(3\times 3=9\), the square root of \(9\) is \(3\).
\[x=\pm \frac{1}{3}\]

Decimal Form: ±0.333333