$$-3\sqrt{32x}+6\sqrt{8x}$$
$0$
$$3\left(-4\sqrt{2}\sqrt{x}+4\sqrt{2}\sqrt{x}\right)$$
$$\sqrt{x}\left(-4\sqrt{2}+4\sqrt{2}\right)$$
$$3\sqrt{x}\left(-4\sqrt{2}+4\sqrt{2}\right)$$
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