How to solve - 30 = - 152e

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve - 30 = - 152e | Equatix

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3(r+2s)=2t-4

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$$-30=-152e$$

Verify

$\text{false}$

Solution Steps

Divide both sides by $-152$.

$$\frac{-30}{-152}=e$$

Reduce the fraction $\frac{-30}{-152}$ to lowest terms by extracting and canceling out $-2$.

$$\frac{15}{76}=e$$

Compare $\frac{15}{76}$ and $e$.

$$\text{false}$$

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