How to solve -3x-4/3=8/3-x

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -3x-4/3=8/3-x | Equatix

Integers & Absolute Values

Factors & Multiples

Prime Factorization

Basic Equations & Inequalities

Coordinate Plane & Graphing

Linear Equations & Inequalities

Quadratic Equations

Polynomials & Factoring

Functions & Graphs

Systems of Equations

Trigonometric Functions

Trigonometric Identities & Equations

Right Triangle Trigonometry

Unit Circle

Graphing Trigonometric Functions

Limits & Continuity

Derivatives & Applications

Integrals & Applications

Series & Sequences

Multivariable Calculus

Functions & Graphs

Polynomial & Rational Functions

Exponential & Logarithmic Functions

Conic Sections

Sequences & Series

Descriptive Statistics

Eigenvalues & Eigenvectors

Linear Transformations

Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$-3x-4/3=8/3-x$$

Solve for x

$x=-2$

Steps for Solving Linear Equation

Add $x$ to both sides.

$$-3x-\frac{4}{3}+x=\frac{8}{3}$$

Combine $-3x$ and $x$ to get $-2x$.

$$-2x-\frac{4}{3}=\frac{8}{3}$$

Add $\frac{4}{3}$ to both sides.

$$-2x=\frac{8}{3}+\frac{4}{3}$$

Since $\frac{8}{3}$ and $\frac{4}{3}$ have the same denominator, add them by adding their numerators.

$$-2x=\frac{8+4}{3}$$

Add $8$ and $4$ to get $12$.

$$-2x=\frac{12}{3}$$

Divide $12$ by $3$ to get $4$.

$$-2x=4$$

Divide both sides by $-2$.

$$x=\frac{4}{-2}$$

Divide $4$ by $-2$ to get $-2$.

$$x=-2$$

Show Solution

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Example

Question

Solve for x

Steps for Solving Linear Equation