Solve for \(x\) in \(-3x-(4-2x)=x-4\).
Solve for \(x\).
\[-3x-(4-2x)=x-4\]
Remove parentheses.
\[-3x-4+2x=x-4\]
Cancel \(-4\) on both sides.
\[-3x+2x=x\]
Simplify \(-3x+2x\) to \(-x\).
\[-x=x\]
Subtract \(-x\) from both sides.
\[0=x+x\]
Simplify \(x+x\) to \(2x\).
\[0=2x\]
Divide both sides by \(2\).
\[0=x\]
Switch sides.
\[x=0\]
\[x=0\]
Substitute \(x=0\) into \(-x-(5x-1)=8-(3x-8)\).
Start with the original equation.
\[-x-(5x-1)=8-(3x-8)\]
Let \(x=0\).
\[-0-5\times 0+1=8-3\times 0+8\]
Simplify.
\[1=16\]
\[1=16\]
Since \(1=16\) is not true, this is an inconsistent system.
