How to solve -3x+8 > 4

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -3x+8 > 4 | Equatix

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$$-3x+8 > 4$$

$x<\frac{4}{3}$

Subtract $8$ from both sides.

$$-3x>4-8$$

Subtract $8$ from $4$ to get $-4$.

$$-3x>-4$$

Divide both sides by $-3$. Since $-3$ is negative, the inequality direction is changed.

$$x<\frac{-4}{-3}$$

Fraction $\frac{-4}{-3}$ can be simplified to $\frac{4}{3}$ by removing the negative sign from both the numerator and the denominator.

$$x<\frac{4}{3}$$