$$-3x^{2}-5x+3x^{2}-4x+2=$$
$2-9x$
$$-5x-4x+2$$
$$-9x+2$$
Show Solution
Hide Solution
$-9$
$$\frac{\mathrm{d}}{\mathrm{d}x}(-5x-4x+2)$$
$$\frac{\mathrm{d}}{\mathrm{d}x}(-9x+2)$$
$$-9x^{1-1}$$
$$-9x^{0}$$
$$-9$$