How to solve -4/9--7/15

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -4/9--7/15 | Equatix

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$$-4/9--7/15$$

$\frac{1}{45}\approx 0.022222222$

Fraction $\frac{-4}{9}$ can be rewritten as $-\frac{4}{9}$ by extracting the negative sign.

$$-\frac{4}{9}-\frac{-7}{15}$$

Fraction $\frac{-7}{15}$ can be rewritten as $-\frac{7}{15}$ by extracting the negative sign.

$$-\frac{4}{9}-\left(-\frac{7}{15}\right)$$

The opposite of $-\frac{7}{15}$ is $\frac{7}{15}$.

$$-\frac{4}{9}+\frac{7}{15}$$

Least common multiple of $9$ and $15$ is $45$. Convert $-\frac{4}{9}$ and $\frac{7}{15}$ to fractions with denominator $45$.

$$-\frac{20}{45}+\frac{21}{45}$$

Since $-\frac{20}{45}$ and $\frac{21}{45}$ have the same denominator, add them by adding their numerators.

$$\frac{-20+21}{45}$$

Add $-20$ and $21$ to get $1$.

$$\frac{1}{45}$$

$\frac{1}{3 ^ {2} \cdot 5} = 0.022222222222222223$