$$- 4 - ( - 3 ) \div 45 \times 3 - 3 ( - 4 )$$
$\frac{41}{5}=8.2$
$$-4-\left(-\frac{1}{15}\times 3\right)-3\left(-4\right)$$
$$-4-\frac{-3}{15}-3\left(-4\right)$$
$$-4-\left(-\frac{1}{5}\right)-3\left(-4\right)$$
$$-4+\frac{1}{5}-3\left(-4\right)$$
$$-\frac{20}{5}+\frac{1}{5}-3\left(-4\right)$$
$$\frac{-20+1}{5}-3\left(-4\right)$$
$$-\frac{19}{5}-3\left(-4\right)$$
$$-\frac{19}{5}-\left(-12\right)$$
$$-\frac{19}{5}+12$$
$$-\frac{19}{5}+\frac{60}{5}$$
$$\frac{-19+60}{5}$$
$$\frac{41}{5}$$
Show Solution
Hide Solution
$\frac{41}{5} = 8\frac{1}{5} = 8.2$
