How to solve -4(3-5)+2(2-3)+7

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -4(3-5)+2(2-3)+7 | Equatix

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3(r+2s)=2t-4

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3(r+2s)=2t-4

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Question

$$-4(3-5)+2(2-3)+7$$

Evaluate

$13$

Solution Steps

Subtract $5$ from $3$ to get $-2$.

$$-4\left(-2\right)+2\left(2-3\right)+7$$

Multiply $-4$ and $-2$ to get $8$.

$$8+2\left(2-3\right)+7$$

Subtract $3$ from $2$ to get $-1$.

$$8+2\left(-1\right)+7$$

Multiply $2$ and $-1$ to get $-2$.

$$8-2+7$$

Subtract $2$ from $8$ to get $6$.

$$6+7$$

Add $6$ and $7$ to get $13$.

$$13$$

Show Solution

Factor

$13$

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