Solve -4[(-6\times3)\div(-9)+1]= | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$-4[(-6 \times 3) \div (-9)+1]=$$

Evaluate

$-12$

Solution Steps

Multiply $-6$ and $3$ to get $-18$.

$$-4\left(\frac{-18}{-9}+1\right)$$

Divide $-18$ by $-9$ to get $2$.

$$-4\left(2+1\right)$$

Add $2$ and $1$ to get $3$.

$$-4\times 3$$

Multiply $-4$ and $3$ to get $-12$.

$$-12$$

Factor

$-12$