Question

$$-40 { x }^{ 2 } +20x=0$$

Answer

x=0,1/2

Solution


Factor out the common term \(20x\).
\[-20x(2x-1)=0\]
Divide both sides by \(-20\).
\[x(2x-1)=0\]
Solve for \(x\).
\[x=0,\frac{1}{2}\]

Decimal Form: 0, 0.5