How to solve -4C imes9C

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -4C\times9C | Equatix

Integers & Absolute Values

Factors & Multiples

Prime Factorization

Basic Equations & Inequalities

Coordinate Plane & Graphing

Linear Equations & Inequalities

Quadratic Equations

Polynomials & Factoring

Functions & Graphs

Systems of Equations

Trigonometric Functions

Trigonometric Identities & Equations

Right Triangle Trigonometry

Unit Circle

Graphing Trigonometric Functions

Limits & Continuity

Derivatives & Applications

Integrals & Applications

Series & Sequences

Multivariable Calculus

Functions & Graphs

Polynomial & Rational Functions

Exponential & Logarithmic Functions

Conic Sections

Sequences & Series

Descriptive Statistics

Eigenvalues & Eigenvectors

Linear Transformations

Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$-4C \times 9C$$

Evaluate

$-36C^{2}$

Show Solution

Differentiate w.r.t. C

$-72C$

Steps Using Definition of a Derivative

Multiply $C$ and $C$ to get $C^{2}$.

$$\frac{\mathrm{d}}{\mathrm{d}C}(-4C^{2}\times 9)$$

Multiply $-4$ and $9$ to get $-36$.

$$\frac{\mathrm{d}}{\mathrm{d}C}(-36C^{2})$$

The derivative of $ax^{n}$ is $nax^{n-1}$.

$$2\left(-36\right)C^{2-1}$$

Multiply $2$ times $-36$.

$$-72C^{2-1}$$

Subtract $1$ from $2$.

$$-72C^{1}$$

For any term $t$, $t^{1}=t$.

$$-72C$$

Show Solution

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Example

Question

Evaluate

Solution Steps

Differentiate w.r.t. C

Steps Using Definition of a Derivative