How to solve -4x+7 > -5

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -4x+7 > -5 | Equatix

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3(r+2s)=2t-4

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3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$-4x+7 > -5$$

Solve for x

$x<3$

Solution Steps

Subtract $7$ from both sides.

$$-4x>-5-7$$

Subtract $7$ from $-5$ to get $-12$.

$$-4x>-12$$

Divide both sides by $-4$. Since $-4$ is negative, the inequality direction is changed.

$$x<\frac{-12}{-4}$$

Divide $-12$ by $-4$ to get $3$.

$$x<3$$

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