1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -5=+0=4 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

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$$-5=+0=4$$

Verify

$\text{false}$

Solution Steps

Compare $-5$ and $0$.

$$\text{false}\text{ and }0=4$$

Compare $0$ and $4$.

$$\text{false}\text{ and }\text{false}$$

The conjunction of $\text{false}$ and $\text{false}$ is $\text{false}$.

$$\text{false}$$

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