$$-5(u-19)\le-6+2u$$
$u\geq \frac{101}{7}$
$$-5u+95\leq -6+2u$$
$$-5u+95-2u\leq -6$$
$$-7u+95\leq -6$$
$$-7u\leq -6-95$$
$$-7u\leq -101$$
$$u\geq \frac{-101}{-7}$$
$$u\geq \frac{101}{7}$$
Show Solution
Hide Solution