Question

$$-5isTheRootOf \frac{ x2=25 }{ }$$

Answer

o=(25*IM)/(sTh*eRo)

Solution


Regroup terms.
\[-5\imath sTheRootOf(2x=25)/\]
Divide both sides by \(-5\).
\[\imath sTheRoo=\frac{5}{\frac{}{-5}}\]
Invert and multiply.
\[\imath sTheRoo=5\times -5\]
Simplify  \(5\times -5\)  to  \(-25\).
\[\imath sTheRoo=-25\]
Divide both sides by \(\imath \).
\[sTheRoo=-\frac{25}{\imath }\]
Rationalize the denominator: \(\frac{25}{\imath } \cdot \frac{\imath }{\imath }=-25\imath \).
\[sTheRoo=-(-25\imath )\]
Remove parentheses.
\[sTheRoo=25\imath \]
Divide both sides by \(sTh\).
\[eRoo=\frac{25\imath }{sTh}\]
Divide both sides by \(eRo\).
\[o=\frac{\frac{25\imath }{sTh}}{eRo}\]
Simplify  \(\frac{\frac{25\imath }{sTh}}{eRo}\)  to  \(\frac{25\imath }{sTheRo}\).
\[o=\frac{25\imath }{sTheRo}\]