How to solve -6/12+15/24

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -6/12+15/24 | Equatix

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$$-6/12+15/24$$

$\frac{1}{8}=0.125$

Reduce the fraction $\frac{-6}{12}$ to lowest terms by extracting and canceling out $6$.

$$-\frac{1}{2}+\frac{15}{24}$$

Reduce the fraction $\frac{15}{24}$ to lowest terms by extracting and canceling out $3$.

$$-\frac{1}{2}+\frac{5}{8}$$

Least common multiple of $2$ and $8$ is $8$. Convert $-\frac{1}{2}$ and $\frac{5}{8}$ to fractions with denominator $8$.

$$-\frac{4}{8}+\frac{5}{8}$$

Since $-\frac{4}{8}$ and $\frac{5}{8}$ have the same denominator, add them by adding their numerators.

$$\frac{-4+5}{8}$$

Add $-4$ and $5$ to get $1$.

$$\frac{1}{8}$$

$\frac{1}{2 ^ {3}} = 0.125$